![]() the include function is case-sensitive.For example myArray.includes("Rob", 2) will return true if the "Rob" value is found only after the index 2 of the array. it takes a second optional argument, as the index from there to start the search.Some final notes on the include() function: result2 = false Notes on the Javascript include() function Let result2 = s2.every(i => myArray.includes(i)) Let result1 = s1.every(i => myArray.includes(i)) On the other side, if we want to check if ALL values are present in a Javascript array, we will use includes() combined with the every() method: const myArray = result2 = false Check for all values to be included in an array ![]() Let result2 = s2.some(i => myArray.includes(i)) Let result1 = s1.some(i => myArray.includes(i)) We can do this by mixing the includes() function and the some() function: const myArray = Let's say we want to test if AT LEAST ONE value, from a given set, is present in a Javascript array. Check for at least one value to be included in an array Unfortunately the includes() function does not have a multiple values search option, but we can simulate this with the help of others Javascript array functions. The Javascript array includes() function will return true if a value is found in an array or false otherwise.īut is it possible to add multiple conditions to this function? Something like this: myArray.includes("one", "two", "three")
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